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v-text-field slots: Right-justify the content and label of a
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Right-justify the content and label of a · Issue ...
In the below code typing in the text field does not update the item quantity. How can the code be altered so that it does?
4) 3x² - 15x² ex³y² <- 2) 4x² - 12 xy + 2x¹z¹ (3) 3x²(x - y) = x + y 3x (x + 2) - x-2 ô 5x(x-3) - 4 (3-x) 6) 5x (x-2y) + 10 (2-x) 7) 2x (3x - 1) +1-32 2) 4
Đáp án:
$\text{1) 3x² - 15x³}$
= $\text{3x² . (1 - 5x)}$
$\text{~~~~~~~~~~~~~~}$
$\text{2) 4x³ - 12x²y + 8x²y²}$
= $\text{4x².(x - 3y + 2y²)}$
$\text{~~~~~~~~~~~~~~}$
$\text{3) 3x²(x - y) - x + y}$
= $\text{3x²(x - y) - (x - y)}$
= $\text{(x - y)(3x² - 1)}$
$\text{~~~~~~~~~~~~~~}$
$\text{4) 3x(x + 2) - x - 2}$
= $\text{3x(x + 2) - (x + 2)}$
= $\text{(x + 2)(3x - 1)}$
$\text{~~~~~~~~~~~~~~}$
$\text{5) 5x²(x - 3) - 4(3 - x)}$
= $\text{5x²(x - 3) - 4(-x + 3)}$
= $\text{5x² - 15x² + 4x - 12}$
= $\text{(x - 3)(5x² + 4)}$
$\text{~~~~~~~~~~~~~~}$
$\text{6) 5x(x - 2y) + 10(2y - x)}$
= $\text{5x(x - 2y) - 10(x - 2y)}$
= $\text{(x - 2y)(5x - 10)}$
$\text{~~~~~~~~~~~~~~}$
$\text{7) 2x(3x - 1) + 1 - 3x}$
= $\text{2x(3x - 1) - (3x - 1)}$
= $\text{(3x - 1)(2x - 1)}$
$\text{~~~~~~~~~~~~~~}$
$\text{8) 4x(2x - 1) + 1 - 2x}$
= $\text{4x(2x - 1) - (2x - 1)}$
= $\text{(2x - 1)(4x - 1)}$
$\text{~~~~~~~~~~~~~~}$
$\text{9) 2x²(x - y) - x + y}$
= $\text{2x²(x - y) - (x - y)}$
= $\text{(x - y)(2x² - 1)}$
$\text{~~~~~~~~~~~~~~}$
$\text{10) 3x(x - y) - 3(y - x)}$
= $\text{3x(x - y) - 3(-x + y)}$
= $\text{3x² - 3xy + 3x - 3y}$
= $\text{(3x² + 3x) - (3xy + 3y)}$
= $\text{3x(x + 1) - 3y(x + 1)}$
= $\text{(x + 1)(3x - 3y)}$
= $\text{3(x - y)(x + 1)}$
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`5`. `B`.is `->` was
vì:Ta có công thức:
`\text{ S+wish(es)+S+V(lùi thì)+.... }`
`-` `\text{ Nên "is" lùi thì về thành "was" ( HTĐ lùi về thành QKĐ ) }`
`6`.`A`. depressing `->` depressed
vì:Ta có :
`\text{ adj dùng với người ta dùng adj dưới dạng -ed }`
`\text{ adj dùng với vật ta dùng adj dưới dạng -ing }`
`->` `\text{ Ba là người nên ta dùng adj dưới dạng -ed }`
`->` `\text{ Dùng "depressed : chán nản " }`
`7`. `C`. has gone `->` had gone
vì:Ta có công thức:
`\text{ S+asked/told/....+(S2/O)+if/whether+S+V(lùi thì)+.... }`
`-` `\text{ Nên "has gone " chuyển thành "had gone" (HTHT lùi thành QKHT ) }`
$#Nu:)))$
QTable with Action Buttons.
(Note in underlying v-text-field this slot overrides append-outer-icon prop.).
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